$$\left. \begin{array} { l } { 9 + 2.5 \div 0.5 - 1 \quad 1.2 } \\ { 9 + 2.5 \div 0.5 - 1 \quad 1.2 } \\ { 8.5 + 1.7 + 1.2 } \\ { ( 8.5 + 1.7 + 1.2 ) - 1.2 } \end{array} \right.$$
$2.8,2.8,10.2,11.4$
$$sort(9+\frac{25}{5}-11.2,9+\frac{2.5}{0.5}-11.2,8.5+1.7+1.2,8.5+1.7+1.2-1.2)$$
$$sort(9+5-11.2,9+\frac{2.5}{0.5}-11.2,8.5+1.7+1.2,8.5+1.7+1.2-1.2)$$
$$sort(14-11.2,9+\frac{2.5}{0.5}-11.2,8.5+1.7+1.2,8.5+1.7+1.2-1.2)$$
$$sort(2.8,9+\frac{2.5}{0.5}-11.2,8.5+1.7+1.2,8.5+1.7+1.2-1.2)$$
$$sort(2.8,9+\frac{25}{5}-11.2,8.5+1.7+1.2,8.5+1.7+1.2-1.2)$$
$$sort(2.8,9+5-11.2,8.5+1.7+1.2,8.5+1.7+1.2-1.2)$$
$$sort(2.8,14-11.2,8.5+1.7+1.2,8.5+1.7+1.2-1.2)$$
$$sort(2.8,2.8,8.5+1.7+1.2,8.5+1.7+1.2-1.2)$$
$$sort(2.8,2.8,10.2+1.2,8.5+1.7+1.2-1.2)$$
$$sort(2.8,2.8,11.4,8.5+1.7+1.2-1.2)$$
$$sort(2.8,2.8,11.4,10.2+1.2-1.2)$$
$$sort(2.8,2.8,11.4,11.4-1.2)$$
$$sort(2.8,2.8,11.4,10.2)$$
$$2.8$$
$$2.8,2.8$$
$$2.8,2.8,11.4$$
$$2.8,2.8,10.2,11.4$$
Show Solution
Hide Solution
$2.8,\ 2.8,\ 11.4,\ 10.2$