Question

$$\left. \begin{array} { l } { a \div ( b + c ) \neq ( a \div b ) + ( a \div c ) } \\ { a = - 10 , b = 1 c = 1 } \end{array} \right.$$

Evaluate (complex solution)

$\frac{a}{b+c}\neq \frac{a\left(b+c\right)}{bc},\ a=-10,\ b=1\text{ and }c=1$

Solve for c

$c=1$
$a=-10\text{ and }b=1$

Solve for b

$b=1$
$a=-10\text{ and }c=1$