$$\left. \begin{array} { l } { a - 8 a c , 3 a c - a , a - c } \\ { x + 11 - 3 \quad 11 - x + 3 , x - 4 + 3 } \end{array} \right.$$
$297a\left(1-x\right)\left(3c-1\right)\left(8c-1\right)\left(a-c\right)$
$a\left(1-8c\right),\ a\left(3c-1\right),\ a-c,\ -297,\ x-1$
