Question

$$\left. \begin{array} { l } { = 1850 } \\ { = 8 \% } \\ { = 9 } \end{array} \right.$$

Answer

$$y=(4627*Sa*ePr*c)/(59*Mo*b^2*m^2)$$

Solution


Cancel \(\imath \) on both sides.
\[Moble\times 59mb\times 4my=18508SalePrce\]
Take out the constants.
\[(59\times 4)bblmmyMoe=18508SalePrce\]
Simplify  \(59\times 4\)  to  \(236\).
\[236bblmmyMoe=18508SalePrce\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[236{b}^{2}l{m}^{2}yMoe=18508SalePrce\]
Regroup terms.
\[236Moe{b}^{2}l{m}^{2}y=18508SalePrce\]
Regroup terms.
\[236Moe{b}^{2}l{m}^{2}y=18508SaePrelc\]
Cancel \(e\) on both sides.
\[236Mo{b}^{2}l{m}^{2}y=18508SaePrlc\]
Cancel \(l\) on both sides.
\[236Mo{b}^{2}{m}^{2}y=18508SaePrc\]
Divide both sides by \(236\).
\[Mo{b}^{2}{m}^{2}y=\frac{18508SaePrc}{236}\]
Simplify  \(\frac{18508SaePrc}{236}\)  to  \(\frac{4627SaePrc}{59}\).
\[Mo{b}^{2}{m}^{2}y=\frac{4627SaePrc}{59}\]
Divide both sides by \(Mo\).
\[{b}^{2}{m}^{2}y=\frac{\frac{4627SaePrc}{59}}{Mo}\]
Simplify  \(\frac{\frac{4627SaePrc}{59}}{Mo}\)  to  \(\frac{4627SaePrc}{59Mo}\).
\[{b}^{2}{m}^{2}y=\frac{4627SaePrc}{59Mo}\]
Divide both sides by \({b}^{2}\).
\[{m}^{2}y=\frac{\frac{4627SaePrc}{59Mo}}{{b}^{2}}\]
Simplify  \(\frac{\frac{4627SaePrc}{59Mo}}{{b}^{2}}\)  to  \(\frac{4627SaePrc}{59Mo{b}^{2}}\).
\[{m}^{2}y=\frac{4627SaePrc}{59Mo{b}^{2}}\]
Divide both sides by \({m}^{2}\).
\[y=\frac{\frac{4627SaePrc}{59Mo{b}^{2}}}{{m}^{2}}\]
Simplify  \(\frac{\frac{4627SaePrc}{59Mo{b}^{2}}}{{m}^{2}}\)  to  \(\frac{4627SaePrc}{59Mo{b}^{2}{m}^{2}}\).
\[y=\frac{4627SaePrc}{59Mo{b}^{2}{m}^{2}}\]