Question

$$\left. \begin{array} { l } { = 3 b ^ { 3 } + 2 a b ^ { 2 } } \\ { 3 x ^ { 3 } + 5 x ^ { 2 } - 4 x , x ^ { 3 } - 6 + 3 x ^ { 2 } , 6 = x ^ { 2 } - x } \\ { - 3 x ^ { 3 } + 5 x ^ { 2 } - 4 x + x ^ { 3 } - 6 + 3 x ^ \right.$$

Answer

$$3*b^3+2*a*b^2!3*x^3+5*x^2-4*x^4-6+3*x^2;6-x^2-623*x$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\begin{aligned}&3{b}^{3}+2a{b}^{2!3}{x}^{3}+5{x}^{2}-4{x}^{1+3}-6+3{x}^{2}\\&6-{x}^{2}-x\times 623\end{aligned}\]
Simplify  \(1+3\)  to  \(4\).
\[\begin{aligned}&3{b}^{3}+2a{b}^{2!3}{x}^{3}+5{x}^{2}-4{x}^{4}-6+3{x}^{2}\\&6-{x}^{2}-x\times 623\end{aligned}\]
Regroup terms.
\[\begin{aligned}&3{b}^{3}+2a{b}^{2!3}{x}^{3}+5{x}^{2}-4{x}^{4}-6+3{x}^{2}\\&6-{x}^{2}-623x\end{aligned}\]