Question

$$\left. \begin{array} { l } { = 71647 } \\ { \cos 645 = \frac { 2 \times 28 } { 125 + 6 } } \\ { \frac { + 3394 } { 404 } } \end{array} \right.$$

Answer

$$X=cos(t)/(9.0105698899180*10^12*Co*t*s)$$

Solution


Cancel \(s\) on both sides.
\[\cos{t}=71647Cots\times 125763394X\]
Regroup terms.
\[\cos{t}=71647\times 125763394CotsX\]
Divide both sides by \(71647\).
\[\frac{\cos{t}}{71647}=125763394CotsX\]
Divide both sides by \(125763394\).
\[\frac{\frac{\cos{t}}{71647}}{125763394}=CotsX\]
Simplify  \(\frac{\frac{\cos{t}}{71647}}{125763394}\)  to  \(\frac{\cos{t}}{71647\times 125763394}\).
\[\frac{\cos{t}}{71647\times 125763394}=CotsX\]
Simplify  \(71647\times 125763394\)  to  \(9.010570\times {10}^{12}\).
\[\frac{\cos{t}}{9.010570\times {10}^{12}}=CotsX\]
Divide both sides by \(Co\).
\[\frac{\frac{\cos{t}}{9.010570\times {10}^{12}}}{Co}=tsX\]
Simplify  \(\frac{\frac{\cos{t}}{9.010570\times {10}^{12}}}{Co}\)  to  \(\frac{\cos{t}}{9.010570\times {10}^{12}Co}\).
\[\frac{\cos{t}}{9.010570\times {10}^{12}Co}=tsX\]
Divide both sides by \(t\).
\[\frac{\frac{\cos{t}}{9.010570\times {10}^{12}Co}}{t}=sX\]
Simplify  \(\frac{\frac{\cos{t}}{9.010570\times {10}^{12}Co}}{t}\)  to  \(\frac{\cos{t}}{9.010570\times {10}^{12}Cot}\).
\[\frac{\cos{t}}{9.010570\times {10}^{12}Cot}=sX\]
Divide both sides by \(s\).
\[\frac{\frac{\cos{t}}{9.010570\times {10}^{12}Cot}}{s}=X\]
Simplify  \(\frac{\frac{\cos{t}}{9.010570\times {10}^{12}Cot}}{s}\)  to  \(\frac{\cos{t}}{9.010570\times {10}^{12}Cots}\).
\[\frac{\cos{t}}{9.010570\times {10}^{12}Cots}=X\]
Switch sides.
\[X=\frac{\cos{t}}{9.010570\times {10}^{12}Cots}\]