Question

$$\left. \begin{array} { l } { = } \\ { 50 c m } \\ { 8 i d e ^ { 2 } } \\ { = 48 c m } \end{array} \right.$$

Answer

$$p=(48*c*m)/(Hy*e^3*eOn*IM*o*t*n*u*s^2*d)$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[Hypot{e}^{3}nu{s}^{2}eOn\imath d=48cm\]
Regroup terms.
\[Hy{e}^{3}eOn\imath potnu{s}^{2}d=48cm\]
Divide both sides by \(Hy\).
\[{e}^{3}eOn\imath potnu{s}^{2}d=\frac{48cm}{Hy}\]
Divide both sides by \({e}^{3}\).
\[eOn\imath potnu{s}^{2}d=\frac{\frac{48cm}{Hy}}{{e}^{3}}\]
Simplify  \(\frac{\frac{48cm}{Hy}}{{e}^{3}}\)  to  \(\frac{48cm}{Hy{e}^{3}}\).
\[eOn\imath potnu{s}^{2}d=\frac{48cm}{Hy{e}^{3}}\]
Divide both sides by \(eOn\).
\[\imath potnu{s}^{2}d=\frac{\frac{48cm}{Hy{e}^{3}}}{eOn}\]
Simplify  \(\frac{\frac{48cm}{Hy{e}^{3}}}{eOn}\)  to  \(\frac{48cm}{Hy{e}^{3}eOn}\).
\[\imath potnu{s}^{2}d=\frac{48cm}{Hy{e}^{3}eOn}\]
Divide both sides by \(\imath \).
\[potnu{s}^{2}d=\frac{\frac{48cm}{Hy{e}^{3}eOn}}{\imath }\]
Simplify  \(\frac{\frac{48cm}{Hy{e}^{3}eOn}}{\imath }\)  to  \(\frac{48cm}{Hy{e}^{3}eOn\imath }\).
\[potnu{s}^{2}d=\frac{48cm}{Hy{e}^{3}eOn\imath }\]
Divide both sides by \(o\).
\[ptnu{s}^{2}d=\frac{\frac{48cm}{Hy{e}^{3}eOn\imath }}{o}\]
Simplify  \(\frac{\frac{48cm}{Hy{e}^{3}eOn\imath }}{o}\)  to  \(\frac{48cm}{Hy{e}^{3}eOn\imath o}\).
\[ptnu{s}^{2}d=\frac{48cm}{Hy{e}^{3}eOn\imath o}\]
Divide both sides by \(t\).
\[pnu{s}^{2}d=\frac{\frac{48cm}{Hy{e}^{3}eOn\imath o}}{t}\]
Simplify  \(\frac{\frac{48cm}{Hy{e}^{3}eOn\imath o}}{t}\)  to  \(\frac{48cm}{Hy{e}^{3}eOn\imath ot}\).
\[pnu{s}^{2}d=\frac{48cm}{Hy{e}^{3}eOn\imath ot}\]
Divide both sides by \(n\).
\[pu{s}^{2}d=\frac{\frac{48cm}{Hy{e}^{3}eOn\imath ot}}{n}\]
Simplify  \(\frac{\frac{48cm}{Hy{e}^{3}eOn\imath ot}}{n}\)  to  \(\frac{48cm}{Hy{e}^{3}eOn\imath otn}\).
\[pu{s}^{2}d=\frac{48cm}{Hy{e}^{3}eOn\imath otn}\]
Divide both sides by \(u\).
\[p{s}^{2}d=\frac{\frac{48cm}{Hy{e}^{3}eOn\imath otn}}{u}\]
Simplify  \(\frac{\frac{48cm}{Hy{e}^{3}eOn\imath otn}}{u}\)  to  \(\frac{48cm}{Hy{e}^{3}eOn\imath otnu}\).
\[p{s}^{2}d=\frac{48cm}{Hy{e}^{3}eOn\imath otnu}\]
Divide both sides by \({s}^{2}\).
\[pd=\frac{\frac{48cm}{Hy{e}^{3}eOn\imath otnu}}{{s}^{2}}\]
Simplify  \(\frac{\frac{48cm}{Hy{e}^{3}eOn\imath otnu}}{{s}^{2}}\)  to  \(\frac{48cm}{Hy{e}^{3}eOn\imath otnu{s}^{2}}\).
\[pd=\frac{48cm}{Hy{e}^{3}eOn\imath otnu{s}^{2}}\]
Divide both sides by \(d\).
\[p=\frac{\frac{48cm}{Hy{e}^{3}eOn\imath otnu{s}^{2}}}{d}\]
Simplify  \(\frac{\frac{48cm}{Hy{e}^{3}eOn\imath otnu{s}^{2}}}{d}\)  to  \(\frac{48cm}{Hy{e}^{3}eOn\imath otnu{s}^{2}d}\).
\[p=\frac{48cm}{Hy{e}^{3}eOn\imath otnu{s}^{2}d}\]