$$\left. \begin{array} { l } { \frac { 2 c } { 9 } - \frac { c - 1 } { 6 } = \frac { c + 3 } { 12 } } \end{array} \right.$$
$c=-3$
$$4\times 2c-6\left(c-1\right)=3\left(c+3\right)$$
$$8c-6\left(c-1\right)=3\left(c+3\right)$$
$$8c-6c+6=3\left(c+3\right)$$
$$2c+6=3\left(c+3\right)$$
$$2c+6=3c+9$$
$$2c+6-3c=9$$
$$-c+6=9$$
$$-c=9-6$$
$$-c=3$$
$$c=-3$$
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