Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$\left. \begin{array} { l } { \frac { 36 } { 192 } + \frac { 12 } { 144 } } \\ { = \frac { 9 } { 16 } \times \frac { 4 } { 12 } ] + [ \frac { 9 } { 16 } \times - \frac { 3 } { 9 } ) } \end{array} \right.$$

Answer

(492144[9*4)/(16*12])-[9/(16*3])

Solution


Simplify  \(\frac{3}{9}\)  to  \(\frac{1}{3}\).
492144\(\frac{9}{16}\times \frac{4}{12}\)+\(\frac{9}{16}\times \frac{-1}{3}\)
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
(492144\(9\times 4\))+\(\frac{9}{16}\times \frac{-1}{3}\)
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
(492144\(9\times 4\))+(-\(9\))
Move the negative sign to the left.
(492144\(9\times 4\))-\(9/\))
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