Question

$$\left. \begin{array} { l } { \frac { p 1 N \cdot 15 } { 2 a \times 3 b ^ { 2 } \times 4 c \times 6 a ^ { 2 } \times 5 b ^ { 3 } } } \\ { = 2 \times 3 } \end{array} \right.$$

Answer

$$c=-(6*X-PIN)/(54720*a^3*b^5)$$

Solution


Take out the constants.
\[PIN-(152\times 3\times 4\times 6\times 5)a{a}^{2}{b}^{2}{b}^{3}c=2X\times 3\]
Simplify  \(152\times 3\)  to  \(456\).
\[PIN-(456\times 4\times 6\times 5)a{a}^{2}{b}^{2}{b}^{3}c=2X\times 3\]
Simplify  \(456\times 4\)  to  \(1824\).
\[PIN-(1824\times 6\times 5)a{a}^{2}{b}^{2}{b}^{3}c=2X\times 3\]
Simplify  \(1824\times 6\)  to  \(10944\).
\[PIN-(10944\times 5)a{a}^{2}{b}^{2}{b}^{3}c=2X\times 3\]
Simplify  \(10944\times 5\)  to  \(54720\).
\[PIN-54720a{a}^{2}{b}^{2}{b}^{3}c=2X\times 3\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[PIN-54720{a}^{1+2}{b}^{2+3}c=2X\times 3\]
Simplify  \(1+2\)  to  \(3\).
\[PIN-54720{a}^{3}{b}^{2+3}c=2X\times 3\]
Simplify  \(2+3\)  to  \(5\).
\[PIN-54720{a}^{3}{b}^{5}c=2X\times 3\]
Simplify  \(2X\times 3\)  to  \(6X\).
\[PIN-54720{a}^{3}{b}^{5}c=6X\]
Subtract \(PIN\) from both sides.
\[-54720{a}^{3}{b}^{5}c=6X-PIN\]
Divide both sides by \(-54720\).
\[{a}^{3}{b}^{5}c=-\frac{6X-PIN}{54720}\]
Divide both sides by \({a}^{3}\).
\[{b}^{5}c=-\frac{\frac{6X-PIN}{54720}}{{a}^{3}}\]
Simplify  \(\frac{\frac{6X-PIN}{54720}}{{a}^{3}}\)  to  \(\frac{6X-PIN}{54720{a}^{3}}\).
\[{b}^{5}c=-\frac{6X-PIN}{54720{a}^{3}}\]
Divide both sides by \({b}^{5}\).
\[c=-\frac{\frac{6X-PIN}{54720{a}^{3}}}{{b}^{5}}\]
Simplify  \(\frac{\frac{6X-PIN}{54720{a}^{3}}}{{b}^{5}}\)  to  \(\frac{6X-PIN}{54720{a}^{3}{b}^{5}}\).
\[c=-\frac{6X-PIN}{54720{a}^{3}{b}^{5}}\]