Since the power of 25 is odd, the result will be negative.
\[\frac{-{4}^{25}{x}^{12}{y}^{5}}{{(-4)}^{4}{x}^{5}{y}^{3}}\times 558x\]
Simplify \({4}^{25}\) to \(1.125900\times {10}^{15}\).
\[\frac{-1.125900\times {10}^{15}{x}^{12}{y}^{5}}{{(-4)}^{4}{x}^{5}{y}^{3}}\times 558x\]
Since the power of 4 is even, the result will be positive.
\[\frac{-1.125900\times {10}^{15}{x}^{12}{y}^{5}}{{4}^{4}{x}^{5}{y}^{3}}\times 558x\]
Simplify \({4}^{4}\) to \(256\).
\[\frac{-1.125900\times {10}^{15}{x}^{12}{y}^{5}}{256{x}^{5}{y}^{3}}\times 558x\]
Move the negative sign to the left.
\[-\frac{1.125900\times {10}^{15}{x}^{12}{y}^{5}}{256{x}^{5}{y}^{3}}\times 558x\]
Take out the constants.
\[-\frac{1.125900}{256}\times \frac{{10}^{15}{x}^{12}{y}^{5}}{{x}^{5}{y}^{3}}\times 558x\]
Simplify \(\frac{1.125900}{256}\) to \(0.004398\).
\[-0.004398\times \frac{{10}^{15}{x}^{12}{y}^{5}}{{x}^{5}{y}^{3}}\times 558x\]
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[-\frac{0.004398\times {10}^{15}{x}^{12}{y}^{5}\times 558x}{{x}^{5}{y}^{3}}\]
Take out the constants.
\[-\frac{(0.004398\times 558){x}^{12}x{y}^{5}\times {10}^{15}}{{x}^{5}{y}^{3}}\]
Simplify \(0.004398\times 558\) to \(2.454110\).
\[-\frac{2.454110{x}^{12}x{y}^{5}\times {10}^{15}}{{x}^{5}{y}^{3}}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[-\frac{2.454110{x}^{12+1}{y}^{5}\times {10}^{15}}{{x}^{5}{y}^{3}}\]
Simplify \(12+1\) to \(13\).
\[-\frac{2.454110{x}^{13}{y}^{5}\times {10}^{15}}{{x}^{5}{y}^{3}}\]
Regroup terms.
\[-\frac{2.454110\times {10}^{15}{x}^{13}{y}^{5}}{{x}^{5}{y}^{3}}\]
Use Quotient Rule: \(\frac{{x}^{a}}{{x}^{b}}={x}^{a-b}\).
\[-2.454110\times {10}^{15}{x}^{13-5}{y}^{5-3}\]
Simplify \(13-5\) to \(8\).
\[-2.454110\times {10}^{15}{x}^{8}{y}^{5-3}\]
Simplify \(5-3\) to \(2\).
\[-2.454110\times {10}^{15}{x}^{8}{y}^{2}\]
-2.454109953196*10^15*x^8*y^2