Question

$$\left. \begin{array} { l } { f y } \\ { 2 x + 3 = 7 + x } \end{array} \right.$$

Answer

r=(x+4)/(2*Ve*IM*f*y*x)

Solution


Regroup terms.
\[2Ve\imath rfyx+3=7+x\]
Regroup terms.
\[3+2Ve\imath rfyx=7+x\]
Subtract \(3\) from both sides.
\[2Ve\imath rfyx=7+x-3\]
Simplify  \(7+x-3\)  to  \(x+4\).
\[2Ve\imath rfyx=x+4\]
Divide both sides by \(2\).
\[Ve\imath rfyx=\frac{x+4}{2}\]
Divide both sides by \(Ve\).
\[\imath rfyx=\frac{\frac{x+4}{2}}{Ve}\]
Simplify  \(\frac{\frac{x+4}{2}}{Ve}\)  to  \(\frac{x+4}{2Ve}\).
\[\imath rfyx=\frac{x+4}{2Ve}\]
Divide both sides by \(\imath \).
\[rfyx=\frac{\frac{x+4}{2Ve}}{\imath }\]
Simplify  \(\frac{\frac{x+4}{2Ve}}{\imath }\)  to  \(\frac{x+4}{2Ve\imath }\).
\[rfyx=\frac{x+4}{2Ve\imath }\]
Divide both sides by \(f\).
\[ryx=\frac{\frac{x+4}{2Ve\imath }}{f}\]
Simplify  \(\frac{\frac{x+4}{2Ve\imath }}{f}\)  to  \(\frac{x+4}{2Ve\imath f}\).
\[ryx=\frac{x+4}{2Ve\imath f}\]
Divide both sides by \(y\).
\[rx=\frac{\frac{x+4}{2Ve\imath f}}{y}\]
Simplify  \(\frac{\frac{x+4}{2Ve\imath f}}{y}\)  to  \(\frac{x+4}{2Ve\imath fy}\).
\[rx=\frac{x+4}{2Ve\imath fy}\]
Divide both sides by \(x\).
\[r=\frac{\frac{x+4}{2Ve\imath fy}}{x}\]
Simplify  \(\frac{\frac{x+4}{2Ve\imath fy}}{x}\)  to  \(\frac{x+4}{2Ve\imath fyx}\).
\[r=\frac{x+4}{2Ve\imath fyx}\]