Question

$$\left. \begin{array} { l } { - 0.6 + 1 \frac { 3 } { 4 } \times 24 = 41 \cdot 4 } \\ { 41.4 } \end{array} \right.$$

Answer

$$w=1.8454106280193/(Ja*a^2*p*n)$$

Solution


Remove parentheses.
\[\imath \imath -0.6+\frac{13}{4}\times 24=41.4Jawapan\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[{\imath }^{2}-0.6+\frac{13}{4}\times 24=41.4Jawapan\]
Use Square Rule: \({i}^{2}=-1\).
\[-1-0.6+\frac{13}{4}\times 24=41.4Jawapan\]
Use this rule: \(\frac{a}{b} \times c=\frac{ac}{b}\).
\[-1-0.6+\frac{13\times 24}{4}=41.4Jawapan\]
Simplify  \(13\times 24\)  to  \(312\).
\[-1-0.6+\frac{312}{4}=41.4Jawapan\]
Simplify  \(\frac{312}{4}\)  to  \(78\).
\[-1-0.6+78=41.4Jawapan\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[-1-0.6+78=41.4Jaw{a}^{2}pn\]
Simplify  \(-1-0.6\)  to  \(-1.6\).
\[-1.6+78=41.4Jaw{a}^{2}pn\]
Simplify  \(-1.6+78\)  to  \(76.4\).
\[76.4=41.4Jaw{a}^{2}pn\]
Divide both sides by \(41.4\).
\[\frac{76.4}{41.4}=Jaw{a}^{2}pn\]
Simplify  \(\frac{76.4}{41.4}\)  to  \(1.845411\).
\[1.845411=Jaw{a}^{2}pn\]
Divide both sides by \(Ja\).
\[\frac{1.845411}{Ja}=w{a}^{2}pn\]
Divide both sides by \({a}^{2}\).
\[\frac{\frac{1.845411}{Ja}}{{a}^{2}}=wpn\]
Simplify  \(\frac{\frac{1.845411}{Ja}}{{a}^{2}}\)  to  \(\frac{1.845411}{Ja{a}^{2}}\).
\[\frac{1.845411}{Ja{a}^{2}}=wpn\]
Divide both sides by \(p\).
\[\frac{\frac{1.845411}{Ja{a}^{2}}}{p}=wn\]
Simplify  \(\frac{\frac{1.845411}{Ja{a}^{2}}}{p}\)  to  \(\frac{1.845411}{Ja{a}^{2}p}\).
\[\frac{1.845411}{Ja{a}^{2}p}=wn\]
Divide both sides by \(n\).
\[\frac{\frac{1.845411}{Ja{a}^{2}p}}{n}=w\]
Simplify  \(\frac{\frac{1.845411}{Ja{a}^{2}p}}{n}\)  to  \(\frac{1.845411}{Ja{a}^{2}pn}\).
\[\frac{1.845411}{Ja{a}^{2}pn}=w\]
Switch sides.
\[w=\frac{1.845411}{Ja{a}^{2}pn}\]