Question

$$\left. \begin{array} { l } { n = 2 n + ( n - 1 ) d } \\ { = 6 + ( n - 1 ) 7 } \\ { b + 7 n - 1 } \end{array} \right.$$

Answer

d=(71*n-65)/(n-1)

Solution


Regroup terms.
\[d(n-1)=6+(n-1)\times 71\]
Regroup terms.
\[d(n-1)=6+71(n-1)\]
Divide both sides by \(n-1\).
\[d=\frac{6+71(n-1)}{n-1}\]
Convert to common denominators.
\[d=\frac{71n-65}{n-1}\]