Solve Add the additive inverse of (- 12 + 16 - 42/3 * of * 7) to the product of -2, -3 and -4. | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\left. \begin{array} { l } { ( - 12 + 16 - 42 + 3 7 ) - 2 , - 3 - 4 } \\ \end{array} \right.$$

Sort

$-7,-3$

Solution Steps

Add $-12$ and $16$ to get $4$.

$$sort(4-42+37-2,-3-4)$$

Subtract $42$ from $4$ to get $-38$.

$$sort(-38+37-2,-3-4)$$

Add $-38$ and $37$ to get $-1$.

$$sort(-1-2,-3-4)$$

Subtract $2$ from $-1$ to get $-3$.

$$sort(-3,-3-4)$$

Subtract $4$ from $-3$ to get $-7$.

$$sort(-3,-7)$$

To sort the list, start from a single element $-3$.

$$-3$$

Insert $-7$ to the appropriate location in the new list.

$$-7,-3$$

Evaluate

$-3,\ -7$