Question

$$\left. \begin{array} { l } { ( \tan a ) e = } \\ { 24 c m ^ { 2 } d } \\ { 1 e a n + h = 6 c m } \\ { B r e a - 1 h = ? } \end{array} \right.$$

Answer

n=(144*ml*eanth*mBr*c*h)/(Re*g*l)

Solution


Cancel \(c\) on both sides.
\[Retangle=24mleanth\times 6cmBreath\]
Simplify  \(24mleanth\times 6cmBreath\)  to  \(144cathmleanthmBre\).
\[Retangle=144cathmleanthmBre\]
Regroup terms.
\[Retangle=144mleanthmBrecath\]
Cancel \(t\) on both sides.
\[Reangle=144mleanthmBrecah\]
Cancel \(a\) on both sides.
\[Rengle=144mleanthmBrech\]
Cancel \(e\) on both sides.
\[Rengl=144mleanthmBrch\]
Divide both sides by \(Re\).
\[ngl=\frac{144mleanthmBrch}{Re}\]
Divide both sides by \(g\).
\[nl=\frac{\frac{144mleanthmBrch}{Re}}{g}\]
Simplify  \(\frac{\frac{144mleanthmBrch}{Re}}{g}\)  to  \(\frac{144mleanthmBrch}{Reg}\).
\[nl=\frac{144mleanthmBrch}{Reg}\]
Divide both sides by \(l\).
\[n=\frac{\frac{144mleanthmBrch}{Reg}}{l}\]
Simplify  \(\frac{\frac{144mleanthmBrch}{Reg}}{l}\)  to  \(\frac{144mleanthmBrch}{Regl}\).
\[n=\frac{144mleanthmBrch}{Regl}\]