$$\left. \begin{array} { l } { ( x ) = \frac { 1 } { x + d ( x + 1 ) } \times ( x + 1 ) ^ { 2 } + 8 ( x + 1 ) ^ { 2 } + ( x ) - 10 ^ { 2 } + 10 ^ { 2 } } \\ { \text { t a s l a t a k a t \right.$$
$\left\{\begin{matrix}\\x=-1\text{, }&\text{unconditionally}\\x=-\frac{8d+1}{8\left(d+1\right)}\text{, }&d\neq -1\end{matrix}\right.$
