Question

$$\left. \begin{array} { l } { \sin t 2 \cos } \\ { + \tan \alpha } \\ { = } \end{array} \right.$$

Answer

$$IM*t^2*a$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[{t}^{2}\imath a\]
Regroup terms.
\[\imath {t}^{2}a\]