$$\left. \begin{array} { l } { \sqrt { 2 } + \sqrt { 3 } = a \sqrt { 2 } + b \sqrt { 3 } + c \sqrt { 6 } + d } \\ { 4 + \sqrt { 3 } } \end{array} \right.$$
$\sqrt{2}+\sqrt{3}=\sqrt{2}a+\sqrt{3}b+\sqrt{6}c+d,\ \text{false}$
