$$\left. \begin{array} { l } { x } \\ { \quad 8 x - 3 = 4 x + 1 } \end{array} \right.$$
$y=1$
$$8x-3-4x=1$$
$$4x-3=1$$
$$4x=1+3$$
$$4x=4$$
$$x=\frac{4}{4}$$
$$x=1$$
$$y=1$$
$$x=1$$ $$y=1$$
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