$$\left. \begin{array} { l } { x = ( t + 1 ) + ( t ^ { 2 } - 1 ) \quad t - 1 } \end{array} \right.$$
$x=t^{3}$
$$x=t+1+t^{3}-t-1$$
$$x=1+t^{3}-1$$
$$x=t^{3}$$
Show Solution
Hide Solution