Question

$$\left. \begin{array} { l } { x ^ { 2 } = 2 a ^ { 2 } - b ^ { 2 } , y ^ { 2 } = 2 b ^ { 2 } - c ^ { 2 } z ^ { 2 } = 2 c ^ { 2 } - a ^ { 2 } } \\ { x ^ { 2 } + y ^ { 2 \right.$$

Solve for x, y, z (complex solution)

$x=\sqrt{2a^{2}-b^{2}}\text{, }y=\sqrt{2b^{2}-\left(cz\right)^{2}}\text{, }z\in \mathrm{C}$
$x=-\sqrt{2a^{2}-b^{2}}\text{, }y=\sqrt{2b^{2}-\left(cz\right)^{2}}\text{, }z\in \mathrm{C}$
$x=\sqrt{2a^{2}-b^{2}}\text{, }y=-\sqrt{2b^{2}-\left(cz\right)^{2}}\text{, }z\in \mathrm{C}$
$x=-\sqrt{2a^{2}-b^{2}}\text{, }y=-\sqrt{2b^{2}-\left(cz\right)^{2}}\text{, }z\in \mathrm{C}$

Solve for x, y, z

$x=-\sqrt{2a^{2}-b^{2}}\text{, }y=-\sqrt{2b^{2}-\left(cz\right)^{2}}\text{, }z\in \begin{bmatrix}-\frac{\sqrt{2}|b|}{|c|},\frac{\sqrt{2}|b|}{|c|}\end{bmatrix}\text{; }x=-\sqrt{2a^{2}-b^{2}}\text{, }y=-\sqrt{2b^{2}-\left(cz\right)^{2}}\text{, }z\geq -\frac{\sqrt{2}|b|}{|c|}\text{; }x=-\sqrt{2a^{2}-b^{2}}\text{, }y=-\sqrt{2b^{2}-\left(cz\right)^{2}}\text{, }z\in \mathrm{R}\text{; }x=\sqrt{2a^{2}-b^{2}}\text{, }y=-\sqrt{2b^{2}-\left(cz\right)^{2}}\text{, }z\in \begin{bmatrix}-\frac{\sqrt{2}|b|}{|c|},\frac{\sqrt{2}|b|}{|c|}\end{bmatrix}\text{; }x=\sqrt{2a^{2}-b^{2}}\text{, }y=-\sqrt{2b^{2}-\left(cz\right)^{2}}\text{, }z\geq -\frac{\sqrt{2}|b|}{|c|}\text{; }x=\sqrt{2a^{2}-b^{2}}\text{, }y=-\sqrt{2b^{2}-\left(cz\right)^{2}}\text{, }z\in \mathrm{R}\text{; }x=-\sqrt{2a^{2}-b^{2}}\text{, }y=\sqrt{2b^{2}-\left(cz\right)^{2}}\text{, }z\in \begin{bmatrix}-\frac{\sqrt{2}|b|}{|c|},\frac{\sqrt{2}|b|}{|c|}\end{bmatrix}\text{; }x=-\sqrt{2a^{2}-b^{2}}\text{, }y=\sqrt{2b^{2}-\left(cz\right)^{2}}\text{, }z\geq -\frac{\sqrt{2}|b|}{|c|}\text{; }x=-\sqrt{2a^{2}-b^{2}}\text{, }y=\sqrt{2b^{2}-\left(cz\right)^{2}}\text{, }z\in \mathrm{R}\text{; }x=\sqrt{2a^{2}-b^{2}}\text{, }y=\sqrt{2b^{2}-\left(cz\right)^{2}}\text{, }z\in \begin{bmatrix}-\frac{\sqrt{2}|b|}{|c|},\frac{\sqrt{2}|b|}{|c|}\end{bmatrix}\text{; }x=\sqrt{2a^{2}-b^{2}}\text{, }y=\sqrt{2b^{2}-\left(cz\right)^{2}}\text{, }z\geq -\frac{\sqrt{2}|b|}{|c|}\text{; }x=\sqrt{2a^{2}-b^{2}}\text{, }y=\sqrt{2b^{2}-\left(cz\right)^{2}}\text{, }z\in \mathrm{R}\text{, }|a|\geq \frac{\sqrt{2}|b|}{2}\text{ and }c\neq 0$