Question

$$\left. \begin{array} { l } { x ^ { 2 } + 7 x + 10 = \frac { 6 x - 6 } { x ^ { 2 } + 2 x - 15 } } \\ { = 6 ( x - 2 ) ( x + 2 ) } \end{array} \right.$$

Answer

$$(2*Wr*e^2*IM*t^2*h*(x-1))/(x-3)$$

Solution


Factor \({x}^{2}+7x+10\).
\[Wr\imath tethe\times \frac{(x+2)(x+5)}{3x+6}\times \frac{6x-6}{{x}^{2}+2x-15}\]
Factor out the common term \(3\).
\[Wr\imath tethe\times \frac{(x+2)(x+5)}{3(x+2)}\times \frac{6x-6}{{x}^{2}+2x-15}\]
Factor out the common term \(6\).
\[Wr\imath tethe\times \frac{(x+2)(x+5)}{3(x+2)}\times \frac{6(x-1)}{{x}^{2}+2x-15}\]
Factor \({x}^{2}+2x-15\).
\[Wr\imath tethe\times \frac{(x+2)(x+5)}{3(x+2)}\times \frac{6(x-1)}{(x-3)(x+5)}\]
Cancel \(x+5\).
\[Wr\imath tethe\times \frac{x+2}{3(x+2)}\times \frac{6(x-1)}{x-3}\]
Cancel \(x+2\).
\[Wr\imath tethe\times \frac{1}{3}\times \frac{6(x-1)}{x-3}\]
Regroup terms.
\[\frac{1}{3}tthWr\imath ee\times \frac{6(x-1)}{x-3}\]
Simplify.
\[\frac{{t}^{2}hWr\imath ee\times 6(x-1)}{3(x-3)}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\frac{{t}^{2}hWr\imath {e}^{2}\times 6(x-1)}{3(x-3)}\]
Regroup terms.
\[\frac{6Wr{e}^{2}\imath {t}^{2}h(x-1)}{3(x-3)}\]
Simplify.
\[\frac{2Wr{e}^{2}\imath {t}^{2}h(x-1)}{x-3}\]