Question

$$\left. \begin{array} { l } { y \cdot a - 2 x ^ { 6 } } \\ { \frac { x - 3 - 2 | - 1 } { y } | \cdot | 12 | ^ { 3 } } \end{array} \right.$$

Answer

x=sqrt(-y/2-6*o*n+2),-sqrt(-y/2-6*o*n+2)

Solution


Simplify  \(9-2{x}^{2}-3-2-12on\)  to  \(-2{x}^{2}-12on+4\).
\[y=-2{x}^{2}-12on+4\]
Factor out the common term \(2\).
\[y=-2({x}^{2}+6on-2)\]
Divide both sides by \(-2\).
\[-\frac{y}{2}={x}^{2}+6on-2\]
Subtract \(6on\) from both sides.
\[-\frac{y}{2}-6on={x}^{2}-2\]
Add \(2\) to both sides.
\[-\frac{y}{2}-6on+2={x}^{2}\]
Take the square root of both sides.
\[\pm \sqrt{-\frac{y}{2}-6on+2}=x\]
Switch sides.
\[x=\pm \sqrt{-\frac{y}{2}-6on+2}\]