Question

$$\left. \begin{array} { l l } { 221 122 5 } \\ { \begin{array} { l l } { 160 } & { 12.420 } & { 3 , 42 \right.$$

Answer

$$12*HCFa*dLCMo*n*f,315*e^4*IM*a^2*n*d*r^2*s*p*c*t*v*l*y$$

Solution


Regroup terms.
\[12HCFadLCMonf,21and\times 15respect\imath velyare\]
Take out the constants.
\[12HCFadLCMonf,(21\times 15)aandrrspctvlyee\imath ee\]
Simplify  \(21\times 15\)  to  \(315\).
\[12HCFadLCMonf,315aandrrspctvlyee\imath ee\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[12HCFadLCMonf,315{a}^{2}nd{r}^{2}spctvly{e}^{4}\imath \]
Regroup terms.
\[12HCFadLCMonf,315{e}^{4}\imath {a}^{2}nd{r}^{2}spctvly\]