Question

$$\left. \begin{array} { l l l } { | l | c | c | c | c | c | } & { 2 } & { 2 } & { 2 } \\ & { 1 , 84 } & { 1 , 86 } & { 1 , 85 } \\ \end{array} \right.$$

Answer

$$-2122*No*e^3*sTa*m*b*r^2*s^3*d*p*o*t*f*l^2,841,861,891,85$$

Solution


Regroup terms.
\[2122mbrrsssdpotfllNoee\imath sTa\imath e,841,861,891,85\]
Simplify  \(2122mbrrsssdpotfllNoee\imath sTa\imath e\)  to  \(2122mb{r}^{2}{s}^{3}dpotf{l}^{2}Noee\imath sTa\imath e\).
\[2122mb{r}^{2}{s}^{3}dpotf{l}^{2}Noee\imath sTa\imath e,841,861,891,85\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[2122mb{r}^{2}{s}^{3}dpotf{l}^{2}No{e}^{3}{\imath }^{2}sTa,841,861,891,85\]
Use Square Rule: \({i}^{2}=-1\).
\[2122mb{r}^{2}{s}^{3}dpotf{l}^{2}No{e}^{3}\times -1\times sTa,841,861,891,85\]
Simplify  \(2122mb{r}^{2}{s}^{3}dpotf{l}^{2}No{e}^{3}\times -1\times sTa\)  to  \(-2122mb{r}^{2}{s}^{3}dpotf{l}^{2}No{e}^{3}sTa\).
\[-2122mb{r}^{2}{s}^{3}dpotf{l}^{2}No{e}^{3}sTa,841,861,891,85\]
Regroup terms.
\[-2122No{e}^{3}sTamb{r}^{2}{s}^{3}dpotf{l}^{2},841,861,891,85\]