Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$\left. \begin{array} { l l l } { | l | l | l | l | l | l | } & { 06 / 005 } & { E G A + 10 } \\ 5023 & { 43 } & { } & { 6024 } & { \frac { 930 } { 60 } } \\ 37 & { } & { 56 } & \end{array} \right.$$

Answer

$$REG+(806*EGA)/5+1.8495971977481*10^22*l*P-70*P-8156$$

Solution


Simplify  \(\frac{806}{05}\)  to  \(\frac{806}{5}\).
\[REG+\frac{806}{5}EGA+\frac{1013}{5}l\times 91293050234360246037P-70P-8156\]
Simplify  \(\frac{806}{5}EGA\)  to  \(\frac{806EGA}{5}\).
\[REG+\frac{806EGA}{5}+\frac{1013}{5}l\times 91293050234360246037P-70P-8156\]
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[REG+\frac{806EGA}{5}+\frac{1013l\times 91293050234360246037P}{5}-70P-8156\]
Simplify  \(1013l\times 91293050234360246037P\)  to  \((9.247986\times {10}^{22})lP\).
\[REG+\frac{806EGA}{5}+\frac{9.247986\times {10}^{22}lP}{5}-70P-8156\]
Simplify  \(\frac{9.247986\times {10}^{22}lP}{5}\)  to  \(1.849597\times {10}^{22}lP\).
\[REG+\frac{806EGA}{5}+1.849597\times {10}^{22}lP-70P-8156\]
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