Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$\left[\begin{matrix} 3 & 2 & 1 \\4 & 5 & 6 \\7 & 1 & -2 \end{matrix}\right] encontrarinversa$$

Answer

$$([3,2,1],[4,5,6],[7,1,-2])*e^2*IM*n^3*c*o*t*r^3*a^2*v*s$$

Solution


Regroup terms.
n*n*n*c*o*t*r*r*r*a*a*v*s*(\(3,2,1\),\(4,5,6\),\(7,1,-2\))*e*IM*e
Simplify.
n^3*c*o*t*r^3*a^2*v*s*(\(3,2,1\),\(4,5,6\),\(7,1,-2\))*e*IM*e
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
n^3*c*o*t*r^3*a^2*v*s*(\(3,2,1\),\(4,5,6\),\(7,1,-2\))*e^2*IM
Regroup terms.
(\(3,2,1\),\(4,5,6\),\(7,1,-2\))*e^2*IM*n^3*c*o*t*r^3*a^2*v*s
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