Question

$$\left[\begin{matrix} - { \left( { 55 }^{ 2 } \right) }^{ 28 } & /36 & 583 \\86956/3 & 684684 & / { 95 }^{ 2 } 2 \end{matrix}\right]$$

Answer

$$[-2.8860949285781*10^97,/36,583],[86956/3,684684,2]/9025$$

Solution


Use Power Rule: \({({x}^{a})}^{b}={x}^{ab}\).
\(-{55}^{56},\frac{}{36},583\),\(\frac{86956}{3},684684,\frac{}{{95}^{2}}\times 2\)
Simplify  \({55}^{56}\)  to  \(2.886095\times {10}^{97}\).
\(-2.886095\times {10}^{97},\frac{}{36},583\),\(\frac{86956}{3},684684,\frac{}{{95}^{2}}\times 2\)
Simplify  \({95}^{2}\)  to  \(9025\).
\(-2.886095\times {10}^{97},\frac{}{36},583\),\(\frac{86956}{3},684684,\frac{}{9025}\times 2\)
Use this rule: \(\frac{a}{b} \times c=\frac{ac}{b}\).
\(-2.886095\times {10}^{97},\frac{}{36},583\),\(\frac{86956}{3},684684,\times 2\)/9025
\(-2.886095\times {10}^{97},\frac{}{36},583\),\(\frac{86956}{3},684684,2\)/9025