Question

$$\left\{\begin{matrix} \frac{ 7 }{ 2x-3y+6 } = \frac{ 7 }{ 3x-2y-1 } \\ \frac{ 6 }{ x-y+4 } = \frac{ 10 }{ y+2 } \end{matrix}\right.$$

Solve for x, y

$x = \frac{42}{13} = 3\frac{3}{13} \approx 3.230769231$
$y = \frac{49}{13} = 3\frac{10}{13} \approx 3.769230769$