Solve {[x+2=0],[(x)^(2)y=8]:} | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\left\{\begin{matrix} x+2=0 \\ { x }^{ 2 } y=8 \end{matrix}\right.$$

Solve for x, y

$x=-2$
$y=2$

Solution Steps

Consider the first equation. Subtract $2$ from both sides. Anything subtracted from zero gives its negation.

$$x=-2$$

Consider the second equation. Insert the known values of variables into the equation.

$$\left(-2\right)^{2}y=8$$

Calculate $-2$ to the power of $2$ and get $4$.

$$4y=8$$

Divide both sides by $4$.

$$y=\frac{8}{4}$$

Divide $8$ by $4$ to get $2$.

$$y=2$$

The system is now solved.

$$x=-2$$ $$y=2$$