How to solve co- 2 - 3 4 7

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve co- 2 - 3 4 7 | Equatix

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$$\left( \begin{array} { l l } { 2 } & { - 3 } \\ { 4 } & { 7 } \end{array} \right)$$

$26$

Find the determinant of the matrix.

$$det(\left(\begin{matrix}2&-3\\4&7\end{matrix}\right))$$

For the $2\times 2$ matrix $\left(\begin{matrix}a&b\\c&d\end{matrix}\right)$, the determinant is $ad-bc$.

$$2\times 7-\left(-3\times 4\right)$$

Multiply $2$ times $7$.

$$14-\left(-3\times 4\right)$$

Multiply $-3$ times $4$.

$$14-\left(-12\right)$$

Subtract $-12$ from $14$.

$$26$$

$\left(\begin{matrix}2&-3\\4&7\end{matrix}\right)$