Question

$$lim_{h\rightarrow0}\frac{(1+h)^{3}-1}{h}$$

Answer

l<0

Solution


Simplify  \(0\times \frac{{(1+h)}^{3}-1}{h}\)  to  \(0\).
\[l\imath mh->0\]
Regroup terms.
\[-+l\imath mh>0\]
Divide both sides by \(\imath \).
\[-+lmh>0\]
Divide both sides by \(m\).
\[-+lh>0\]
Divide both sides by \(h\).
\[-+l>0\]
Multiply both sides by \(-1\).
\[l<0\]