Factor \({x}^{2}-5x+6\).
Ask: Which two numbers add up to \(-5\) and multiply to \(6\)?
Rewrite the expression using the above.
\[(x-3)(x-2)\]
\[l\imath mx->2\times \frac{(x-3)(x-2)}{x-2}\]
Cancel \(x-2\).
\[l\imath mx->2(x-3)\]
Regroup terms.
\[-+l\imath mx>2(x-3)\]
Divide both sides by \(\imath \).
\[-+lmx>\frac{2(x-3)}{\imath }\]
Rationalize the denominator: \(\frac{2(x-3)}{\imath } \cdot \frac{\imath }{\imath }=-2(x-3)\imath \).
\[-+lmx>-2(x-3)\imath \]
Regroup terms.
\[-+lmx>-2\imath (x-3)\]
Divide both sides by \(m\).
\[-+lx>-\frac{2\imath (x-3)}{m}\]
Divide both sides by \(x\).
\[-+l>-\frac{\frac{2\imath (x-3)}{m}}{x}\]
Simplify \(\frac{\frac{2\imath (x-3)}{m}}{x}\) to \(\frac{2\imath (x-3)}{mx}\).
\[-+l>-\frac{2\imath (x-3)}{mx}\]
Multiply both sides by \(-1\).
\[l<\frac{2\imath (x-3)}{mx}\]
l<(2*IM*(x-3))/(m*x)
