Question

$$lim_{x\rightarrow2}\frac{x^{3}-8}{\sqrt{x-2}}\supset7\frac{0}{0}$$

Answer

$$2*IM*l*m*x^4-8*sqrt(x)-1400*e*s^2*u*p*t$$

Solution


Regroup terms.
\[2lmx{x}^{3}\imath -8\sqrt{x}-2supset\times 700\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[2lm{x}^{1+3}\imath -8\sqrt{x}-2supset\times 700\]
Simplify  \(1+3\)  to  \(4\).
\[2lm{x}^{4}\imath -8\sqrt{x}-2supset\times 700\]
Regroup terms.
\[2\imath lm{x}^{4}-8\sqrt{x}-2supset\times 700\]
Take out the constants.
\[2\imath lm{x}^{4}-8\sqrt{x}-(2\times 700)ssupte\]
Simplify  \(2\times 700\)  to  \(1400\).
\[2\imath lm{x}^{4}-8\sqrt{x}-1400ssupte\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[2\imath lm{x}^{4}-8\sqrt{x}-1400{s}^{2}upte\]
Regroup terms.
\[2\imath lm{x}^{4}-8\sqrt{x}-1400e{s}^{2}upt\]