Question

$$lim_{x\rightarrow2}\frac{x^{n}-2^{n}}{x-2}$$

Answer

$$l<-(2*(x^n-2^n))/(IM*m*x*(x-2))$$

Solution


Simplify  \(2\times \frac{{x}^{n}-{2}^{n}}{x-2}\)  to  \(\frac{2({x}^{n}-{2}^{n})}{x-2}\).
\[l\imath mx->\frac{2({x}^{n}-{2}^{n})}{x-2}\]
Regroup terms.
\[-+l\imath mx>\frac{2({x}^{n}-{2}^{n})}{x-2}\]
Divide both sides by \(\imath \).
\[-+lmx>\frac{\frac{2({x}^{n}-{2}^{n})}{x-2}}{\imath }\]
Simplify  \(\frac{\frac{2({x}^{n}-{2}^{n})}{x-2}}{\imath }\)  to  \(\frac{2({x}^{n}-{2}^{n})}{\imath (x-2)}\).
\[-+lmx>\frac{2({x}^{n}-{2}^{n})}{\imath (x-2)}\]
Divide both sides by \(m\).
\[-+lx>\frac{\frac{2({x}^{n}-{2}^{n})}{\imath (x-2)}}{m}\]
Simplify  \(\frac{\frac{2({x}^{n}-{2}^{n})}{\imath (x-2)}}{m}\)  to  \(\frac{2({x}^{n}-{2}^{n})}{\imath m(x-2)}\).
\[-+lx>\frac{2({x}^{n}-{2}^{n})}{\imath m(x-2)}\]
Divide both sides by \(x\).
\[-+l>\frac{\frac{2({x}^{n}-{2}^{n})}{\imath m(x-2)}}{x}\]
Simplify  \(\frac{\frac{2({x}^{n}-{2}^{n})}{\imath m(x-2)}}{x}\)  to  \(\frac{2({x}^{n}-{2}^{n})}{\imath mx(x-2)}\).
\[-+l>\frac{2({x}^{n}-{2}^{n})}{\imath mx(x-2)}\]
Multiply both sides by \(-1\).
\[l<-\frac{2({x}^{n}-{2}^{n})}{\imath mx(x-2)}\]