Regroup terms.
\[-+l\imath mx>2({x}^{2}-4x+2)\]
Divide both sides by \(\imath \).
\[-+lmx>\frac{2({x}^{2}-4x+2)}{\imath }\]
Rationalize the denominator: \(\frac{2({x}^{2}-4x+2)}{\imath } \cdot \frac{\imath }{\imath }=-2({x}^{2}-4x+2)\imath \).
\[-+lmx>-2({x}^{2}-4x+2)\imath \]
Regroup terms.
\[-+lmx>-2\imath ({x}^{2}-4x+2)\]
Divide both sides by \(m\).
\[-+lx>-\frac{2\imath ({x}^{2}-4x+2)}{m}\]
Divide both sides by \(x\).
\[-+l>-\frac{\frac{2\imath ({x}^{2}-4x+2)}{m}}{x}\]
Simplify \(\frac{\frac{2\imath ({x}^{2}-4x+2)}{m}}{x}\) to \(\frac{2\imath ({x}^{2}-4x+2)}{mx}\).
\[-+l>-\frac{2\imath ({x}^{2}-4x+2)}{mx}\]
Multiply both sides by \(-1\).
\[l<\frac{2\imath ({x}^{2}-4x+2)}{mx}\]
l<(2*IM*(x^2-4*x+2))/(m*x)
