Question

$$lim_{x\rightarrow3}\frac{x-\sqrt{18-x^{2}}}{\sqrt{9+3x^{2}-6}}$$

Answer

$$l<-(3*(x-sqrt(18-x^2)))/(sqrt(3)*IM*m*x*sqrt(x^2+1))$$

Solution


Factor out the common term \(3\).
\[l\imath mx->3\times \frac{x-\sqrt{18-{x}^{2}}}{\sqrt{3(3+{x}^{2}-2)}}\]
Simplify  \(3+{x}^{2}-2\)  to  \({x}^{2}+1\).
\[l\imath mx->3\times \frac{x-\sqrt{18-{x}^{2}}}{\sqrt{3({x}^{2}+1)}}\]
Use Multiplication Distributive Property: \({(xy)}^{a}={x}^{a}{y}^{a}\).
\[l\imath mx->3\times \frac{x-\sqrt{18-{x}^{2}}}{\sqrt{3}\sqrt{{x}^{2}+1}}\]
Simplify  \(3\times \frac{x-\sqrt{18-{x}^{2}}}{\sqrt{3}\sqrt{{x}^{2}+1}}\)  to  \(\frac{3(x-\sqrt{18-{x}^{2}})}{\sqrt{3}\sqrt{{x}^{2}+1}}\).
\[l\imath mx->\frac{3(x-\sqrt{18-{x}^{2}})}{\sqrt{3}\sqrt{{x}^{2}+1}}\]
Regroup terms.
\[-+l\imath mx>\frac{3(x-\sqrt{18-{x}^{2}})}{\sqrt{3}\sqrt{{x}^{2}+1}}\]
Divide both sides by \(\imath \).
\[-+lmx>\frac{\frac{3(x-\sqrt{18-{x}^{2}})}{\sqrt{3}\sqrt{{x}^{2}+1}}}{\imath }\]
Simplify  \(\frac{\frac{3(x-\sqrt{18-{x}^{2}})}{\sqrt{3}\sqrt{{x}^{2}+1}}}{\imath }\)  to  \(\frac{3(x-\sqrt{18-{x}^{2}})}{\sqrt{3}\imath \sqrt{{x}^{2}+1}}\).
\[-+lmx>\frac{3(x-\sqrt{18-{x}^{2}})}{\sqrt{3}\imath \sqrt{{x}^{2}+1}}\]
Divide both sides by \(m\).
\[-+lx>\frac{\frac{3(x-\sqrt{18-{x}^{2}})}{\sqrt{3}\imath \sqrt{{x}^{2}+1}}}{m}\]
Simplify  \(\frac{\frac{3(x-\sqrt{18-{x}^{2}})}{\sqrt{3}\imath \sqrt{{x}^{2}+1}}}{m}\)  to  \(\frac{3(x-\sqrt{18-{x}^{2}})}{\sqrt{3}\imath m\sqrt{{x}^{2}+1}}\).
\[-+lx>\frac{3(x-\sqrt{18-{x}^{2}})}{\sqrt{3}\imath m\sqrt{{x}^{2}+1}}\]
Divide both sides by \(x\).
\[-+l>\frac{\frac{3(x-\sqrt{18-{x}^{2}})}{\sqrt{3}\imath m\sqrt{{x}^{2}+1}}}{x}\]
Simplify  \(\frac{\frac{3(x-\sqrt{18-{x}^{2}})}{\sqrt{3}\imath m\sqrt{{x}^{2}+1}}}{x}\)  to  \(\frac{3(x-\sqrt{18-{x}^{2}})}{\sqrt{3}\imath mx\sqrt{{x}^{2}+1}}\).
\[-+l>\frac{3(x-\sqrt{18-{x}^{2}})}{\sqrt{3}\imath mx\sqrt{{x}^{2}+1}}\]
Multiply both sides by \(-1\).
\[l<-\frac{3(x-\sqrt{18-{x}^{2}})}{\sqrt{3}\imath mx\sqrt{{x}^{2}+1}}\]