Question

$$lim_{x\rightarrow a}=\frac{4x+5}{2x+3}$$

Answer

l=-(IM*(56*x+3))/(m*x*a)

Solution


Simplify  \(4x+52x+3\)  to  \(56x+3\).
\[l\imath mxa=56x+3\]
Divide both sides by \(\imath \).
\[lmxa=\frac{56x+3}{\imath }\]
Rationalize the denominator: \(\frac{56x+3}{\imath } \cdot \frac{\imath }{\imath }=-(56x+3)\imath \).
\[lmxa=-(56x+3)\imath \]
Regroup terms.
\[lmxa=-\imath (56x+3)\]
Divide both sides by \(m\).
\[lxa=-\frac{\imath (56x+3)}{m}\]
Divide both sides by \(x\).
\[la=-\frac{\frac{\imath (56x+3)}{m}}{x}\]
Simplify  \(\frac{\frac{\imath (56x+3)}{m}}{x}\)  to  \(\frac{\imath (56x+3)}{mx}\).
\[la=-\frac{\imath (56x+3)}{mx}\]
Divide both sides by \(a\).
\[l=-\frac{\frac{\imath (56x+3)}{mx}}{a}\]
Simplify  \(\frac{\frac{\imath (56x+3)}{mx}}{a}\)  to  \(\frac{\imath (56x+3)}{mxa}\).
\[l=-\frac{\imath (56x+3)}{mxa}\]