Question

$$lim_{x\rightarrow\infty}(\frac{x+3}{x-1})^{x+1}\cdot\int$$

Answer

$$-l*m*x*n*f*t*y*(4*x-1)^x+int$$

Solution


Collect like terms.
\[l\imath mx\imath nfty{((x+3x)-1)}^{x}+1\times int\]
Simplify  \((x+3x)-1\)  to  \(4x-1\).
\[l\imath mx\imath nfty{(4x-1)}^{x}+1\times int\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[l{\imath }^{2}mxnfty{(4x-1)}^{x}+1\times int\]
Use Square Rule: \({i}^{2}=-1\).
\[l\times -1\times mxnfty{(4x-1)}^{x}+1\times int\]
Simplify  \(l\times -1\times mxnfty{(4x-1)}^{x}\)  to  \(l\times -mxnfty{(4x-1)}^{x}\).
\[l\times -mxnfty{(4x-1)}^{x}+1\times int\]
Regroup terms.
\[-lmxnfty{(4x-1)}^{x}+1\times int\]
Simplify  \(1\times int\)  to  \(int\).
\[-lmxnfty{(4x-1)}^{x}+int\]