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Basic Math
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Example
3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b
Question
$$lim_{x\rightarrow\infty}(\frac{x+3}{x-1})^{x+1}\cdot\int$$
Answer
$$-l*m*x*n*f*t*y*(4*x-1)^x+int$$
Solution
Collect like terms.
\[l\imath mx\imath nfty{((x+3x)-1)}^{x}+1\times int\]
Simplify \((x+3x)-1\) to \(4x-1\).
\[l\imath mx\imath nfty{(4x-1)}^{x}+1\times int\]
Use
Product Rule
: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[l{\imath }^{2}mxnfty{(4x-1)}^{x}+1\times int\]
Use
Square Rule
: \({i}^{2}=-1\).
\[l\times -1\times mxnfty{(4x-1)}^{x}+1\times int\]
Simplify \(l\times -1\times mxnfty{(4x-1)}^{x}\) to \(l\times -mxnfty{(4x-1)}^{x}\).
\[l\times -mxnfty{(4x-1)}^{x}+1\times int\]
Regroup terms.
\[-lmxnfty{(4x-1)}^{x}+1\times int\]
Simplify \(1\times int\) to \(int\).
\[-lmxnfty{(4x-1)}^{x}+int\]
-l*m*x*n*f*t*y*(4*x-1)^x+int
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