Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$lim_{x\rightarrow-1}[(3x+8)\cdot(4x-1)\cdot(x+2)]$$

Answer

l<-(IM*1[(3*x+8)*(4*x-1)*(x+2)])/(m*x)

Solution


Regroup terms.
-+l*IM*m*x>-1\((3x+8)(4x-1)(x+2)\)
Divide both sides by \(\imath \).
-+l*m*x>-(1\((3x+8)(4x-1)(x+2)\))/IM
Rationalize the denominator: )/IM \cdot (IM)/(IM)=-1\((3x+8)(4x-1)(x+2)\)*IM].
-+l*m*x>-(-1\((3x+8)(4x-1)(x+2)\)*IM)
Regroup terms.
-+l*m*x>-(-IM*1\((3x+8)(4x-1)(x+2)\))
Remove parentheses.
-+l*m*x>IM*1\((3x+8)(4x-1)(x+2)\)
Divide both sides by \(m\).
-+l*x>(IM*1\((3x+8)(4x-1)(x+2)\))/m
Divide both sides by \(x\).
-+l>((IM*1\((3x+8)(4x-1)(x+2)\))/m)/x
Simplify  )/m)/x]  to  )/(m*x)].
-+l>(IM*1\((3x+8)(4x-1)(x+2)\))/(m*x)
Multiply both sides by \(-1\).
l<-(IM*1\((3x+8)(4x-1)(x+2)\))/(m*x)
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