Question

$$lim_{x\rightarrow-3}[\frac{y^{3}+243}{y^{3}+27}]$$

Answer

$$l<3[(y^3+243)/(IM*m*x*(y+3)*(y^2-3*y+9)])$$

Solution


Rewrite \({y}^{3}+27\) in the form \({a}^{3}+{b}^{3}\), where \(a=y\) and \(b=3\).
l*IM*m*x->-3\(\frac{{y}^{3}+243}{{y}^{3}+{3}^{3}}\)
Use Sum of Cubes: \({a}^{3}+{b}^{3}=(a+b)({a}^{2}-ab+{b}^{2})\).
l*IM*m*x->-3\(\frac{{y}^{3}+243}{(y+3)({y}^{2}-(y)(3)+{3}^{2})}\)
Simplify  \({3}^{2}\)  to  \(9\).
l*IM*m*x->-3\(\frac{{y}^{3}+243}{(y+3)({y}^{2}-y\times 3+9)}\)
Regroup terms.
l*IM*m*x->-3\(\frac{{y}^{3}+243}{(y+3)({y}^{2}-3y+9)}\)
Regroup terms.
-+l*IM*m*x>-3\(\frac{{y}^{3}+243}{(y+3)({y}^{2}-3y+9)}\)
Divide both sides by \(\imath \).
-+l*m*x>-(3\(\frac{{y}^{3}+243}{(y+3)({y}^{2}-3y+9)}\))/IM
Simplify  )/IM]  to  \(3\(\frac{{y}^{3}+243}{\}\).
-+l*m*x>-3\(({y}^{3}+243)/\))
Divide both sides by \(m\).
-+l*x>-(3\(({y}^{3}+243)/\)))/m
Simplify  ))/m]  to  \(3\(\frac{{y}^{3}+243}{\}\).
-+l*x>-3\(({y}^{3}+243)/\))
Divide both sides by \(x\).
-+l>-(3\(({y}^{3}+243)/\)))/x
Simplify  ))/x]  to  \(3\(\frac{{y}^{3}+243}{\}\).
-+l>-3\(({y}^{3}+243)/\))
Multiply both sides by \(-1\).
l<3\(({y}^{3}+243)/\))