Question

$$lim_{x\rightarrow-5}\frac{8x+x^{2}}{x}$$

Answer

l<-(5*IM*(8+x))/(m*x)

Solution


Factor out the common term \(x\).
\[l\imath mx->-5\times \frac{x(8+x)}{x}\]
Cancel \(x\).
\[l\imath mx->-5(8+x)\]
Regroup terms.
\[-+l\imath mx>-5(8+x)\]
Divide both sides by \(\imath \).
\[-+lmx>-\frac{5(8+x)}{\imath }\]
Rationalize the denominator: \(\frac{5(8+x)}{\imath } \cdot \frac{\imath }{\imath }=-5(8+x)\imath \).
\[-+lmx>-(-5(8+x)\imath )\]
Regroup terms.
\[-+lmx>-(-5\imath (8+x))\]
Remove parentheses.
\[-+lmx>5\imath (8+x)\]
Divide both sides by \(m\).
\[-+lx>\frac{5\imath (8+x)}{m}\]
Divide both sides by \(x\).
\[-+l>\frac{\frac{5\imath (8+x)}{m}}{x}\]
Simplify  \(\frac{\frac{5\imath (8+x)}{m}}{x}\)  to  \(\frac{5\imath (8+x)}{mx}\).
\[-+l>\frac{5\imath (8+x)}{mx}\]
Multiply both sides by \(-1\).
\[l<-\frac{5\imath (8+x)}{mx}\]