Question

$$lng-\frac{2y}{x}=8$$

Solve for g

$g=e^{\frac{2y}{x}+8}$
$x\neq 0$

Solve for x

$\left\{\begin{matrix}x=-\frac{2y}{-\ln(g)+8}\text{, }&y\neq 0\text{ and }g\neq e^{8}\text{ and }g>0\\x\neq 0\text{, }&y=0\text{ and }g=e^{8}\end{matrix}\right.$