$$\log ( 42.42 ) \times \log ( 0.035 ) \times \log ( 2.45 )$$
$\frac{\ln(0.035)\ln(2.45)\ln(42.42)}{\ln(10)^{3}}\approx -0.922180461$
$\frac{\ln(0.035)\ln(2.45)\ln(42.42)}{\ln(10)^{3}}$
