$x=\frac{\left(3\sqrt{5}+7\right)y}{2}$
$x=\frac{\left(7-3\sqrt{5}\right)y}{2}\text{, }y>0$

$y=\frac{\left(3\sqrt{5}+7\right)x}{2}$
$y=\frac{\left(7-3\sqrt{5}\right)x}{2}\text{, }x>0$