Question

$$\log q = \frac { 1 } { \log _ { 2 } }$$

Answer

$$o=1/(Sh*w*t^2*h*a*log(p)*log(q))$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[Show{t}^{2}ha\log{q}=\frac{1}{\log{p}}\]
Divide both sides by \(Sh\).
\[ow{t}^{2}ha\log{q}=\frac{\frac{1}{\log{p}}}{Sh}\]
Simplify  \(\frac{\frac{1}{\log{p}}}{Sh}\)  to  \(\frac{1}{\log{p}Sh}\).
\[ow{t}^{2}ha\log{q}=\frac{1}{\log{p}Sh}\]
Divide both sides by \(w\).
\[o{t}^{2}ha\log{q}=\frac{\frac{1}{\log{p}Sh}}{w}\]
Simplify  \(\frac{\frac{1}{\log{p}Sh}}{w}\)  to  \(\frac{1}{\log{p}Shw}\).
\[o{t}^{2}ha\log{q}=\frac{1}{\log{p}Shw}\]
Divide both sides by \({t}^{2}\).
\[oha\log{q}=\frac{\frac{1}{\log{p}Shw}}{{t}^{2}}\]
Simplify  \(\frac{\frac{1}{\log{p}Shw}}{{t}^{2}}\)  to  \(\frac{1}{Shw{t}^{2}\log{p}}\).
\[oha\log{q}=\frac{1}{Shw{t}^{2}\log{p}}\]
Divide both sides by \(h\).
\[oa\log{q}=\frac{\frac{1}{Shw{t}^{2}\log{p}}}{h}\]
Simplify  \(\frac{\frac{1}{Shw{t}^{2}\log{p}}}{h}\)  to  \(\frac{1}{Shw{t}^{2}h\log{p}}\).
\[oa\log{q}=\frac{1}{Shw{t}^{2}h\log{p}}\]
Divide both sides by \(a\).
\[o\log{q}=\frac{\frac{1}{Shw{t}^{2}h\log{p}}}{a}\]
Simplify  \(\frac{\frac{1}{Shw{t}^{2}h\log{p}}}{a}\)  to  \(\frac{1}{Shw{t}^{2}ha\log{p}}\).
\[o\log{q}=\frac{1}{Shw{t}^{2}ha\log{p}}\]
Divide both sides by \(\log{q}\).
\[o=\frac{\frac{1}{Shw{t}^{2}ha\log{p}}}{\log{q}}\]
Simplify  \(\frac{\frac{1}{Shw{t}^{2}ha\log{p}}}{\log{q}}\)  to  \(\frac{1}{Shw{t}^{2}ha\log{p}\log{q}}\).
\[o=\frac{1}{Shw{t}^{2}ha\log{p}\log{q}}\]