$$\log_{ 5 }({ 25 }) + \log_{ 5 }({ 5 }) + \log_{ 5 }({ 125 })$$
$6$
$$2+\log_{5}\left(5\right)+\log_{5}\left(125\right)$$
$$2+1+\log_{5}\left(125\right)$$
$$3+\log_{5}\left(125\right)$$
$$3+3$$
$$6$$
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$2\times 3$
