Question

$$\lt B P C$$

Answer

$$-Wr*e^3*eBPC*IM*t*n^4*o^2*a^3*d*j*c*l^2*f*g*tan(g)$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[{\imath }^{2}Wr\imath tenonadjacen(\tan{g})leofangleBPC\]
Use Square Rule: \({i}^{2}=-1\).
\[-1\times Wr\imath tenonadjacen(\tan{g})leofangleBPC\]
Regroup terms.
\[-tnnnnooaaadjcllfgWr\imath ee(\tan{g})eeBPC\]
Simplify  \(tnnnnooaaadjcllfgWr\imath ee(\tan{g})eeBPC\)  to  \(t{n}^{4}{o}^{2}{a}^{3}djc{l}^{2}fgWr\imath ee(\tan{g})eeBPC\).
\[-t{n}^{4}{o}^{2}{a}^{3}djc{l}^{2}fgWr\imath ee(\tan{g})eeBPC\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[-t{n}^{4}{o}^{2}{a}^{3}djc{l}^{2}fgWr\imath {e}^{3}(\tan{g})eBPC\]
Regroup terms.
\[-Wr{e}^{3}eBPC\imath t{n}^{4}{o}^{2}{a}^{3}djc{l}^{2}fg\tan{g}\]