Question

$$m c ( b ^ { 2 } + 1 ) + b ( m ^ { 2 } + c ^ { 2 } )$$

Answer

$$m*c*(b^2+1)-Ab*yTe*b*l*t^2*s*(m^2+c^2)$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[mc({b}^{2}+1)+b({m}^{2}+{c}^{2})Ab{\imath }^{2}l{t}^{2}yTes\]
Use Square Rule: \({i}^{2}=-1\).
\[mc({b}^{2}+1)+b({m}^{2}+{c}^{2})Ab\times -1\times l{t}^{2}yTes\]
Simplify  \(b({m}^{2}+{c}^{2})Ab\times -1\times l{t}^{2}yTes\)  to  \(b({m}^{2}+{c}^{2})Ab\times -l{t}^{2}yTes\).
\[mc({b}^{2}+1)+b({m}^{2}+{c}^{2})Ab\times -l{t}^{2}yTes\]
Regroup terms.
\[mc({b}^{2}+1)-AbyTebl{t}^{2}s({m}^{2}+{c}^{2})\]